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	<title>Comments on: How To Mess With Your Neighbors</title>
	<atom:link href="http://endlessorigami.com/2011/08/27/how-to-mess-with-your-neighbors/feed/" rel="self" type="application/rss+xml" />
	<link>http://endlessorigami.com/2011/08/27/how-to-mess-with-your-neighbors/</link>
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	<item>
		<title>By: John Hammond</title>
		<link>http://endlessorigami.com/2011/08/27/how-to-mess-with-your-neighbors/#comment-5514</link>
		<dc:creator>John Hammond</dc:creator>
		<pubDate>Tue, 10 Jan 2012 01:04:00 +0000</pubDate>
		<guid isPermaLink="false">http://endlessorigami.com/?p=712#comment-5514</guid>
		<description>not sure why everyone went to the trouble of some of those steps, and the initial problem wasn&#039;t copied correctly, anyway
log 3 (3^(x+1) - 18) = 2
3^(log 3 (3^(x+1) - 18)) = 3^2
3^(x+1) - 18 = 9
3^(x+1) = 27
log 3 (3^(x+1) = log 3 (27)
x+1 = 3
x = 2

4 less steps.</description>
		<content:encoded><![CDATA[<p>not sure why everyone went to the trouble of some of those steps, and the initial problem wasn&#8217;t copied correctly, anyway<br />
log 3 (3^(x+1) &#8211; 18) = 2<br />
3^(log 3 (3^(x+1) &#8211; 18)) = 3^2<br />
3^(x+1) &#8211; 18 = 9<br />
3^(x+1) = 27<br />
log 3 (3^(x+1) = log 3 (27)<br />
x+1 = 3<br />
x = 2</p>
<p>4 less steps.</p>
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	<item>
		<title>By: Aksthomsen</title>
		<link>http://endlessorigami.com/2011/08/27/how-to-mess-with-your-neighbors/#comment-5239</link>
		<dc:creator>Aksthomsen</dc:creator>
		<pubDate>Tue, 20 Dec 2011 17:16:00 +0000</pubDate>
		<guid isPermaLink="false">http://endlessorigami.com/?p=712#comment-5239</guid>
		<description>I&#039;ve never enjoyd log related problems</description>
		<content:encoded><![CDATA[<p>I&#8217;ve never enjoyd log related problems</p>
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	<item>
		<title>By: WTF</title>
		<link>http://endlessorigami.com/2011/08/27/how-to-mess-with-your-neighbors/#comment-5006</link>
		<dc:creator>WTF</dc:creator>
		<pubDate>Tue, 22 Nov 2011 23:57:00 +0000</pubDate>
		<guid isPermaLink="false">http://endlessorigami.com/?p=712#comment-5006</guid>
		<description>I would rather have the password NOT the answer. Just for shits and giggles when they doubt themselves over and over again. </description>
		<content:encoded><![CDATA[<p>I would rather have the password NOT the answer. Just for shits and giggles when they doubt themselves over and over again.</p>
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	<item>
		<title>By: Zgrgrgzrgdrgzrg</title>
		<link>http://endlessorigami.com/2011/08/27/how-to-mess-with-your-neighbors/#comment-4839</link>
		<dc:creator>Zgrgrgzrgdrgzrg</dc:creator>
		<pubDate>Sun, 06 Nov 2011 17:58:00 +0000</pubDate>
		<guid isPermaLink="false">http://endlessorigami.com/?p=712#comment-4839</guid>
		<description>Who needs math?
http://www.wolframalpha.com/input/?i=log3%283^%28x%2B1%29-18%29+%3D+2</description>
		<content:encoded><![CDATA[<p>Who needs math?<br />
<a href="http://www.wolframalpha.com/input/?i=log3%283" rel="nofollow">http://www.wolframalpha.com/input/?i=log3%283</a>^%28x%2B1%29-18%29+%3D+2</p>
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	<item>
		<title>By: Miguel Angel Leon</title>
		<link>http://endlessorigami.com/2011/08/27/how-to-mess-with-your-neighbors/#comment-4740</link>
		<dc:creator>Miguel Angel Leon</dc:creator>
		<pubDate>Fri, 14 Oct 2011 16:41:00 +0000</pubDate>
		<guid isPermaLink="false">http://endlessorigami.com/?p=712#comment-4740</guid>
		<description>log 3 ( 3^(x+1) ) - 18 = 2
log 3 ( 3^(x+1) ) - 18 = log 3 (3^2)
3^(x+1) - 18 = 3^2
3^(x+1) - 18 - 3^2 = 0
3^(x+1) - 18 - 9 = 0
3^(x+1) - 27 = 0
3^(x+1) = 27
3^(x+1) = 3^3
x+1 = 3
x = 3-1
x = 2

:)

(I just copied and pasted the other 2 guys&#039; response to look smart)</description>
		<content:encoded><![CDATA[<p>log 3 ( 3^(x+1) ) &#8211; 18 = 2<br />
log 3 ( 3^(x+1) ) &#8211; 18 = log 3 (3^2)<br />
3^(x+1) &#8211; 18 = 3^2<br />
3^(x+1) &#8211; 18 &#8211; 3^2 = 0<br />
3^(x+1) &#8211; 18 &#8211; 9 = 0<br />
3^(x+1) &#8211; 27 = 0<br />
3^(x+1) = 27<br />
3^(x+1) = 3^3<br />
x+1 = 3<br />
x = 3-1<br />
x = 2<br />
 <img src='http://endlessorigami.com/wp-includes/images/smilies/icon_smile.gif' alt=':)' class='wp-smiley' /> </p>
<p>(I just copied and pasted the other 2 guys&#8217; response to look smart)</p>
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	<item>
		<title>By: Anonymous</title>
		<link>http://endlessorigami.com/2011/08/27/how-to-mess-with-your-neighbors/#comment-4724</link>
		<dc:creator>Anonymous</dc:creator>
		<pubDate>Sat, 08 Oct 2011 21:05:00 +0000</pubDate>
		<guid isPermaLink="false">http://endlessorigami.com/?p=712#comment-4724</guid>
		<description>Psh, both of you guys got it wrong. It&#039;s not log base 3, it&#039;s log base 10 of 3(x^(x+1)-18).

x=(ln((100/3)+18)/ln3)-1.</description>
		<content:encoded><![CDATA[<p>Psh, both of you guys got it wrong. It&#8217;s not log base 3, it&#8217;s log base 10 of 3(x^(x+1)-18).</p>
<p>x=(ln((100/3)+18)/ln3)-1.</p>
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		<title>By: Ryan</title>
		<link>http://endlessorigami.com/2011/08/27/how-to-mess-with-your-neighbors/#comment-4581</link>
		<dc:creator>Ryan</dc:creator>
		<pubDate>Thu, 01 Sep 2011 04:10:00 +0000</pubDate>
		<guid isPermaLink="false">http://endlessorigami.com/?p=712#comment-4581</guid>
		<description>psh still dealing with single variable math? I would make the problem more like finding the function of the normal plane to a point on a conic surface. ;)</description>
		<content:encoded><![CDATA[<p>psh still dealing with single variable math? I would make the problem more like finding the function of the normal plane to a point on a conic surface. <img src='http://endlessorigami.com/wp-includes/images/smilies/icon_wink.gif' alt=';)' class='wp-smiley' /> </p>
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	<item>
		<title>By: Kessuk</title>
		<link>http://endlessorigami.com/2011/08/27/how-to-mess-with-your-neighbors/#comment-4564</link>
		<dc:creator>Kessuk</dc:creator>
		<pubDate>Sun, 28 Aug 2011 18:27:00 +0000</pubDate>
		<guid isPermaLink="false">http://endlessorigami.com/?p=712#comment-4564</guid>
		<description>Easier (for me):
log 3 (3^(x+1) - 18) = 2
3^2 = 3^(x+1) - 18
9 = 3^(x+1) - 18
3^(x+1) = 9 + 18
3^(x+1) = 27
3^(x+1) = 3^3
x+1 = 3
x = 3 - 1
x = 2

:)</description>
		<content:encoded><![CDATA[<p>Easier (for me):<br />
log 3 (3^(x+1) &#8211; 18) = 2<br />
3^2 = 3^(x+1) &#8211; 18<br />
9 = 3^(x+1) &#8211; 18<br />
3^(x+1) = 9 + 18<br />
3^(x+1) = 27<br />
3^(x+1) = 3^3<br />
x+1 = 3<br />
x = 3 &#8211; 1<br />
x = 2<br />
 <img src='http://endlessorigami.com/wp-includes/images/smilies/icon_smile.gif' alt=':)' class='wp-smiley' /> </p>
]]></content:encoded>
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	<item>
		<title>By: Stefan Niculae</title>
		<link>http://endlessorigami.com/2011/08/27/how-to-mess-with-your-neighbors/#comment-4563</link>
		<dc:creator>Stefan Niculae</dc:creator>
		<pubDate>Sun, 28 Aug 2011 14:00:00 +0000</pubDate>
		<guid isPermaLink="false">http://endlessorigami.com/?p=712#comment-4563</guid>
		<description>log 3 ( 3^(x+1) ) - 18 = 2
log 3 ( 3^(x+1) ) - 18 = log 3 (3^2)
3^(x+1) - 18 = 3^2
3^(x+1) - 18 - 3^2 = 0
3^(x+1) - 18 - 9 = 0
3^(x+1) - 27 = 0
3^(x+1) = 27
3^(x+1) = 3^3
x+1 = 3
x = 3-1
x = 2

:)
</description>
		<content:encoded><![CDATA[<p>log 3 ( 3^(x+1) ) &#8211; 18 = 2<br />
log 3 ( 3^(x+1) ) &#8211; 18 = log 3 (3^2)<br />
3^(x+1) &#8211; 18 = 3^2<br />
3^(x+1) &#8211; 18 &#8211; 3^2 = 0<br />
3^(x+1) &#8211; 18 &#8211; 9 = 0<br />
3^(x+1) &#8211; 27 = 0<br />
3^(x+1) = 27<br />
3^(x+1) = 3^3<br />
x+1 = 3<br />
x = 3-1<br />
x = 2<br />
 <img src='http://endlessorigami.com/wp-includes/images/smilies/icon_smile.gif' alt=':)' class='wp-smiley' /> </p>
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